Write a program to print size of a structure.
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
struct p0
{
};
struct p1
{
char ch;
};
struct p2
{
char ch;
short int d;
};
struct p3
{
char ch;
int d;
};
struct person
{
char name[10];
int age;
float salary;
}v0={"Start"},v1,v2={"IDC",25,52000.00};
int main()
{
struct person v3 = {"AB"};
struct person v4 = {98};
struct person v5;
struct person v6;
static struct person v7;
struct person v8;
struct person v9;
struct person v10;
struct person v11 = {.salary = 35};
struct person *ptr;
struct person *ptr2;
v5.age = 43;
strcpy(v6.name,"What");
printf("Size of structure p0 = %d\n",sizeof(struct p0));
printf("Size of structure p1 = %d\n",sizeof(struct p1));
printf("Size of structure p2 = %d\n",sizeof(struct p2));
printf("Size of structure p3 = %d\n",sizeof(struct p3));
printf("Size of structure person = %d\n",sizeof(struct person));
printf("v0 = %s %d %f\n",v0.name,v0.age,v0.salary);
printf("v1 = %s %d %f\n",v1.name,v1.age,v1.salary);
printf("v2 = %s %d %f\n",v2.name,v2.age,v2.salary);
printf("v3 = %s %d %f\n",v3.name,v3.age,v3.salary);
printf("v4 = %s %d %f\n",v4.name,v4.age,v4.salary);
printf("v5 = %s %d %f\n",v5.name,v5.age,v5.salary);
printf("v6 = %s %d %f\n",v6.name,v6.age,v6.salary);
printf("v7 = %s %d %f\n",v7.name,v7.age,v7.salary);
printf("Enter Name = ");
scanf("%[^\n]",v8.name);
printf("Enter Age = ");
scanf("%d",&v8.age);
printf("Enter Salary = ");
scanf("%f",&v8.salary);
printf("v8 = %s %d %f\n",v8.name,v8.age,v8.salary);
printf("Enter Age = ");
scanf("%d",&v9.age);
printf("v9 = %s %d %f\n",v9.name,v9.age,v9.salary);
ptr = (struct person*)malloc(sizeof(struct person));
ptr = &v2;
printf("v2 = %s %d %f\n",ptr->name,ptr->age,ptr->salary);
v10 = v2;
printf("v10 = %s %d %f\n",v10.name,v10.age,v10.salary);
printf("v11 = %s %d %f\n",v11.name,v11.age,v11.salary);
ptr2 = (struct person*)malloc(sizeof(struct person));
printf("Enter Name = ");
scanf(" %[^\n]",ptr2->name);
printf("Enter Age = ");
scanf("%d",&ptr2->age);
printf("Enter salary = ");
scanf("%f",&ptr2->salary);
printf("ptr2 = %s %d %f\n",ptr2->name,ptr2->age,ptr2->salary);
return 0;
}
Output
Size of structure p0 = 0 Size of structure p1 = 1 Size of structure p2 = 4 Size of structure p3 = 8 Size of structure person = 20 v0 = Start 0 0.000000 v1 = 0 0.000000 v2 = IDC 25 52000.000000 v3 = AB 0 0.000000 v4 = b 0 0.000000 v5 = ��� 43 0.000000 v6 = What 0 0.000000 v7 = 0 0.000000 Enter Name = Joe Enter Age = 23 Enter Salary = 23453 v8 = Joe 23 23453.000000 Enter Age = 54 v9 = Љ�� 54 -0.000015 v2 = IDC 25 52000.000000 v10 = IDC 25 52000.000000 v11 = 0 35.000000 Enter Name = etr Enter Age = 43 Enter salary = 94764 ptr2 = etr 43 94764.000000