Reverse the bits of a number

Write a program to reverse the bits of a given number.

#include<stdio.h>
void Print_Num_inBinary(int);
void Reverse_Bits(int*);
int main()
{
	int num,bit,status;
	printf("Enter a Number = ");
	scanf("%d",&num);
	Print_Num_inBinary(num);
	Reverse_Bits(&num);
	printf("Bits are reversed now");
	Print_Num_inBinary(num);
	return 0;
}
void Print_Num_inBinary(int n)
{
	int i;
	printf("\n%d Bit Binary Representation of a Number\n",sizeof(int)*8);
	for(i = ((sizeof(int)*8)-1);i >= 0;i--)
	{
		printf("%d",n >> i & 1);
		if(!(i%8))
			printf(" ");
	}
	printf("\n");
}
void Reverse_Bits(int *n)
{
	int i,j;
	for(i = (sizeof(int)*8-1),j=0;j<i;i--,j++)
	{
		if(((*n) >> i & 1) != ((*n) >> j & 1))
		{
			*n = *n ^ 1 << i;
			*n = *n ^ 1 << j;
		}
	}
}

Output

Enter a Number = 65535
32 Bit Binary Representation of a Number
00000000 00000000 11111111 11111111
Bits are reversed now
32 Bit Binary Representation of a Number
11111111 11111111 00000000 00000000

Enter a Number = 15
32 Bit Binary Representation of a Number
00000000 00000000 00000000 00001111
Bits are reversed now
32 Bit Binary Representation of a Number
11110000 00000000 00000000 00000000